3х^2+5х-10=4х+4
3х^2+х-14=0
D=1^2-4×3×(-14)=169
x1=(-1+13)/6=2
x2=(-1-13)/6=-7/3
![+ \left \{ {{ x^{2} +y=7} \atop {2 x^{2} -y=5}} \right.](https://tex.z-dn.net/?f=%2B+%5Cleft+%5C%7B+%7B%7B+x%5E%7B2%7D+%2By%3D7%7D+%5Catop+%7B2+x%5E%7B2%7D+-y%3D5%7D%7D+%5Cright.+)
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3x² = 12
x² = 4
x₁ = 2 x₂ = - 2
y₁ = 7 - x² = 7 - 2² = 7 - 4 = 3
y₂ = 7 - x² = 7 - (- 2)² = 7 - 4 = 3
Ответ : (2 ; 3) , (- 2 ; 3)
Ответ:
Объяснение:
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