(5х-1)(2х+1)-(3х-7)^2>5(9х-1)-67
10x²-2x+5x-1-(9x²-42x+49)>45x-5-67
10x²+3x-1-9x²+42x-49>45x-72
x²+45x-50>45x-72
x²>50-72
x²>-22
Неравенство верно, т.к. для любых х∈R х² ≥0, а число -22 <0
<span>8(х-3)-4(5х+2)=5х+19,
8х-8·3-4·5х-4·2=5х+19,
8х-24-20х-8=5х+19,
8х-20х-5х=19+24+8,
-17х=51,
х=51:(-17)
х=-3
</span>
1
(8y²+2y)/(2y-1)(4y²+2y+1)-(2y-1)/(4y²+2y+1)=
=(8y²+2y-4y²+1)/(2y-1)(4y²+2y+1)=(4y²+2y+1)/(2y-1)(4y²+2y+1)=1/(2y-1)
2
1+(2y+1)/2y-(4y²+10y)/2y(2y+1)=(4y²+2y+4y²+4y+1-4y²-10y)/2y(2y+1)=
=(4y²-4y+1)/2y(2y+1)=(2y-1)²/2y(2y+1)
3
1/(2y-1)*(2y-1)²/2y(2y+1)=(2y-1)/2y(2y+1)
4
(2y-1)/2y(2y+1):1/2y=(2y-1)/2y(2y+1) *2y=(2y-1)/(2y+1)