<span>-0,6х+3*(х-0,4)+11=-2,5х+3*(х+2);
-0.6x+3x-1.2+11=-2.5+3x+6;
-0.6x+3x-3x=-2.5+6+1.2-11;
-0.6x=-6.3
х=-6.3:(-0.6_
х=10.5
</span><span>4(х-0,5)=7(х+1);
</span>4х-2=7х+7
4х-7х=7+2
-3х=9
х=9:(-3)
х=-3
1) 1/2
2)-1/3
3)a(3)3 и есть <span>знаменатель
4) -1/2</span>
-10x=9-25x
15x=9
x=0,6
y=-10*0,6=-6
Loq_8(Loq_14 196) + Loq_7 √7 =Loq_8 2 + 1/2 = -1/2 +2 =1,5 .
------------------
3^(Loq_√3 7 -2Loq_1/3 7) =3^(Loq_3 7² +2Loq_3 7) =
3^(Loq_3 7² +Loq_3 7²) = 3^(Loq_3 7²* 7²) =3^(Loq_3 7⁴) =7⁴ =2401.
------------------
0,7( 2+(√3)^(Loq_3 1/16) ) ^ Loq_9/4 3 =0,7( 2+(√3)^(Loq_√ 3 1/4) ) ^ Loq_9/4 3 =0,7( 2+ 1/4) ) ^ Loq_9/4 3 =0,7*(9/4) ^ Loq_9/4 3 = 0,7*3 =2,1.
*******************
a^(Loq_a M ) =M ;
Loq_a M + Loq_a N = Loq_a M * N ;
Loq_a^m b^n =(n/m) *Loq_a b.
3/4*1/2=2л
0,375=2л
х=2*1/0,375=5,3л
Ответ: 5,3л