Question

Преобразуйте в многочлен.1) (0, 6+2x)^22) (4a+1/8b)^23) (12a-0, 3c)^2

Answer 1

1) (0,6+2х)^2=0.6^2+(2x)^2=0.36+4x^2
2) (4a+1/8b)^2=(4a)^2+(1/8b)^2=16a^2+1/64b^2
3) (12a-0, 3c)^2=(12a)^2-(0.3c)^2=144a^2-0.09c^2