косинус(квадрат) (альфа)= 1- синус(квадрат) (альфа)
1
Прибавим
2cosx=1
cosx=1/2
x=+-π/3
Отнимем
2siny=0
siny=0
y=0
(-π/3;0);(π/3;0)
2
y-x=3⇒y=x+3
sinπx-sinπy=√3
sinπx-sin(πx+3π)=√3
sinπx+sinπx=√3
2sinπx=√3
sinπx=√3/2
πx=π/6 U πx=5π/6
x=1/6 U x=5/6
y=3 1/6 U y=3 5/6
(1/6;3 1/6);(5/6;3 5/6)
3
Прибавим
sinxcosy+cosxsiny=1⇒sin(x+y)=1⇒x+y=π/2
отнимем
sinxcosy-cosxsiny=1/2⇒sin(x-y)=1/2⇒x-y=π/6
прибавим
2x=2π/3⇒x=π/3
отнимем
2y=π/3⇒y=π/6
(π/3;π/6)
Это означает, что нужно записать в виде двойного неравенства.![2)x=0,4\pm0,15\\\\0,4-0,15<x<0,4+0,15\\\\0,25<x<0,55\\\\4)x=0,73\pm0,01\\\\0,73-0,01<x<0,73+0,01\\\\0,72<x<0,74\\\\6)x=-2\frac{1}{5}\pm\frac{1}{10}\\\\x=-2,2\pm0,1\\\\-2,2-0,1<x<-2,2+0,1\\\\-2,3<x<-2,1](https://tex.z-dn.net/?f=2%29x%3D0%2C4%5Cpm0%2C15%5C%5C%5C%5C0%2C4-0%2C15%3Cx%3C0%2C4%2B0%2C15%5C%5C%5C%5C0%2C25%3Cx%3C0%2C55%5C%5C%5C%5C4%29x%3D0%2C73%5Cpm0%2C01%5C%5C%5C%5C0%2C73-0%2C01%3Cx%3C0%2C73%2B0%2C01%5C%5C%5C%5C0%2C72%3Cx%3C0%2C74%5C%5C%5C%5C6%29x%3D-2%5Cfrac%7B1%7D%7B5%7D%5Cpm%5Cfrac%7B1%7D%7B10%7D%5C%5C%5C%5Cx%3D-2%2C2%5Cpm0%2C1%5C%5C%5C%5C-2%2C2-0%2C1%3Cx%3C-2%2C2%2B0%2C1%5C%5C%5C%5C-2%2C3%3Cx%3C-2%2C1)
Y=3/√(6X-5) + 7/ X² н<span>айдем первообразную:</span>