Question

Tga/sina,a=пи/3 ююююююююююю

Answer 1

$\frac{tg \alpha }{sin \alpha } = \frac{ \frac{sin \alpha }{cos \alpha } }{sin \alpha } = \frac{sin \alpha }{cos \alpha *sin \alpha } = \frac{1}{cos \alpha }$
При $\alpha = \frac{ \pi }{3} :$
$\frac{1}{cos \frac{ \pi }{3} } = \frac{1}{ \frac{1}{2} } =2$