сначала надо немного упростить :
1) 8<span>¹⁶ / 16¹² = 2⁴⁸ / 2⁴⁸ = 1 </span>
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<span>2) (15<span>а²</span><span>- 10ab)/(<span><span>3ab-2b²) = 5а(3а - 2<span><span>b</span></span>)/(<span><span>b</span></span>·<span><span><span><span>(3а - 2<span><span>b</span></span>)</span></span></span></span>) = 5а/<span><span><span><span><span><span>b</span></span></span></span></span></span></span></span></span></span>
При а= -2,b= -0,1
<span><span><span><span>5а/<span><span><span><span><span><span>b</span></span></span></span></span></span></span></span></span></span> = 5·(-2)/(-0,1) = -10/(-0,1) = 100
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1)3x^2+12xy+12y^2=3(x^2+4xy+4y)=3(x+2y)^2 - формула квадрата суммы
2)8a(b-3)+c(3-b)=8a(b-3)-c(b-3)=(b-3)(8a-c)
3)x^2+3x-2xy-6y=x(x+3)-2y(x+3)=(x+3)(x-2y)