1. (3a + b)(c - d) = 3ac + bc - 3ad -bd
2. (3x² - y)(2x - 5y²) = 6x³ - 2xy - 15x²y² + 5y³
3. (2x² - 3x + 1)(4x + 6) - 8x³ = 8x³ - 12x² + 4x + 12x² - 18x + 6 - 8x³ = -14x + 6
4. (3z - 2)(5z + 3) - (2z - 1)(7z + 2) = -4
15z² - 10z + 9z - 6 - (14z² - 7z + 4z - 2) + 4 = 0
15z² - 10z + 9z - 6 - 14z² + 7z - 4z + 2 + 4 = 0
z² + 2z = 0
z(z + 2) = 0
z + 2 = 0 или z = 0
z = -2
Ответ: z = -2
z = 0
5.
=
В приложении, наверно так:
<span>-4x-0,08x=0
</span><span>-4,08x=0
</span>х=0