Question

Решите уравнение 1 \ (х-2)^2 - 1 \ х-2 - 6 = 0

Answer 1

$\frac{1}{(x-2)^2}- \frac{1}{x-2}-6=0 \\ \frac{1-(x-2)-6(x-2)^2}{(x-2)^2} =0 \\ x \neq 2 \\ 1-x+2-6(x^2-4x+4)=0 \\ 1-x+2-6x^2+24x-24=0 \\ -6x^2+23x-21=0 \\ 6x^2-23x+21=0 \\ D=b^2-4ac=529-504=25=5^2 \\ x_1=2 \frac{1}{3} \\ x_2=1,5$