Сумма первых членов геометрической прогрессии вычисляется по формуле:
![S_n= \frac{b_1(q^n-1)}{q-1}, \ q\neq 1\\\\ S_4= \frac{1\cdot(3^4-1)}{3-1} = \frac{1\cdot80}{2} =40](https://tex.z-dn.net/?f=S_n%3D+%5Cfrac%7Bb_1%28q%5En-1%29%7D%7Bq-1%7D%2C+%5C+q%5Cneq+1%5C%5C%5C%5C%0AS_4%3D+%5Cfrac%7B1%5Ccdot%283%5E4-1%29%7D%7B3-1%7D+%3D+%5Cfrac%7B1%5Ccdot80%7D%7B2%7D+%3D40+)
А). -4x^5+y^2*3xy^4= -4x^5+3xy^6; б). (-3x^2y^3)^2=9x^4y^6.
1.1)=3(a+2b)
2)=4(3m-4n)
3)=5c(2k-3p)
4)=8a(x+1)
5)=5b(1-5c)
6)=7x(2x+1)
7)=n^5(n^5-1)
8)=m^6(1+m)
2.1)=266256-516*513=1548
2)0,343+0,7*0,51=0,7
3)0,0016-0,0088*1,2=-0,00896
3. 1)D=<span><span><span><span>(<span>−1</span>)^</span>2</span>−<span><span>4·1</span>·0</span></span>=<span>1−0</span></span>=<span>1
x1=-(-1)+1/2*1=2/2=1
x2=-(-1)-1/2*1=0/2=0
2)D=</span><span><span><span>15^2</span>−<span><span>4·1</span>·0</span></span>=<span>225−0</span></span>=<span>225=15
x1=-15+15/2*1=0/2=0
x2=-15-15/2*1=-30/2=-15
3)D=</span><span><span><span><span><span>(<span>−30</span>)^</span>2</span>−<span><span>4·5</span>·0</span></span>=<span>900−0</span></span>=900=30
x1=-(-30)+30/2*5=60/10=6
x2=-(-30)-30/2*5=0/10=0
4)</span><span><span><span><span>18^2</span>−<span><span>4·14</span>·0</span></span>=<span>324−0</span></span>=324=18
x1=-18+18/2*14=0/28=0
x2=-18-18/2*14=-36/28=-1,28</span>