Question

Сократите дробь: а) 6a+6b _______ 9a в) ab-ad ______ abd д) ax-ay _______ ax+ay ж) axy+ax ________ ax+ axz

Answer 1

А) $\frac{6a+6b}{9a}$ = $\frac{6(a+b)}{9a}$ = $\frac{2(a+b)}{3a}$
в) $\frac{ab-ad}{abd}$ = $\frac{a(b-d)}{abd}$ = $\frac{b-d}{bd}$
д) $\frac{ax-ay}{ax+ay}$ = $\frac{a(x-y)}{a(x+y)}$ = $\frac{x-y}{x+y}$
ж) $\frac{axy+ax}{ax+axz}$ = $\frac{ax(y+1)}{ax(1+z)}$ = $\frac{y+1}{1+z}$

Answer 2

А)(6а+6b)/9a=2(a+b)/3a=(2a+2b)/3a
в)(ab-ad)/abd=a(b-d)/abd=b-d/bd
д)(ax-ay)/(ax+ay)=a(x-y)/a(x+y)=(x-y)/(x+y)
ж)(axy+ax)/(ax+axz)=(ax(y+1))/(ax(1+z))