A) sinx = √3/2; x =
![(-1)^{n} π/3 +πn, [tex] б) /cosx = tgx - √3 =0; tgx = √3; x =arctg√3 +πn, x = π/3 +πn, n∈Z. г)cosx[tex] \neq 0; x \neq \pi /2+ \pi n,n](https://tex.z-dn.net/?f=+%28-1%29%5E%7Bn%7D%C2%A0%CF%80%2F3+%2B%CF%80n%2C+%5Btex%5D%C2%A0+%D0%B1%29+%C2%A0%2Fcosx+%3D+tgx+-%C2%A0%E2%88%9A3+%3D0%3B+%C2%A0tgx+%3D%C2%A0%E2%88%9A3%3B+x+%3Darctg%E2%88%9A3+%2B%CF%80n%2C+%C2%A0x+%3D%C2%A0%CF%80%2F3+%2B%CF%80n%2C+n%E2%88%88Z.+%D0%B3%29cosx%5Btex%5D+%5Cneq+0%3B+++x+%5Cneq++%5Cpi+%2F2%2B+%5Cpi+n%2Cn)
∈Z; sinx (sin2x + 1) = 0;
sinx = 0; x = πn, sin2x =- 1; sinx = -1/2; x =
2) 2 cosx/2 меньше 1; cosx/2 = 1/2; x/2 =π/6 +2πn, n∈Z; x =+- π/3 +πn,n∈z;
23/4+21/5=5.75+4.2=9.95*16=159.2
√28=√4•7=2√7 ; √99-?;√160=4√10 ;√147=7√3
1) 2x-3x=0+40;-1x=40;x=40:(-1);x=-40
<span>1)x^2-100x=0
х(х-100)=0
х=0
х-100=0
х=100
2)9/25(дробь)x^3-x=0
х(9/25х</span>²-1)=0
<span>х=0
(3/5х-1)(</span>3/5х+1)=0
3/5х=1
х=5/3
3/5х+1=0
х=-5/3
<span>3)25y^2+20y+4=0
(5у+2)</span>²=0
<span>5у+2=0
5у=-2
у=-2/5
4)36x^2+25=60x
36х</span>²-60х+25=0
<span>(6х-5)</span>²=0
<span>6х-5=0
6х=5
х=5/6
5)x^4-x^2=0
х</span>²(х²-1)=0
<span>х</span>²=0
<span>х=0
(х-1)(х+1)=0
х=1
х=-1
6)x^5-49x^3=0
х</span>³(х²-7)=0
<span>х</span>³=0
<span>х=0
х</span>²-7=0
<span>х</span>²=7
<span>х=</span>√7
<span>х=-</span>√7<span>
7)x^3+2x^2-9x-18=0
х</span>²(х+2)-9(х+2)=0
<span>(х+2)(х</span>²-9)=0
<span>х+2=0
х=-2
(х-3)(х+3)=0
х=3
х=-3
8)y^3-3y^2-4y+12=0
у</span>²(у-3)-4(у-3)=0
(у²-4)(у-3)=0
(у-2)(у+2)(у-3)=0
у=2
у=-2
у=3