2011=n
2012=n+1
2011²+2011²·2012²+2012²=n^2+n^2*(n+1)^2+(n+1)^2=
=n^2+n^2*(n^2+2n+1)+(n^2+2n+1)=
=n^4+2n^3+3n^2+2n+1=
=n^2*(n^2+2n+3+2/n+1/n^2)=
=n^2*((n+1/n)^2+2(n+1/n)+1)=
=n^2*((n+1/n+1)^2)=
=(n^2+n+1)^2
2011²+2011²·2012²+2012²=(n^2+n+1)^2=(2011^2+2011+1)^2=<span>
4046133</span>^2
А)всі дійсні числа
б)x+16≥0, x≥-16,т.е.,[-16,+нескінч.)
1)20-2х = х-1
x+2x=20+1
3x=21
x=7
2)8х-3 = 5х+6
8x-5x=6+3
3x=9
x=3
3)5х-9 = 7х-13
7x-5x=13-9
2x=4
x=2
4)10х-3 = х+6
10x-x=6+3
9x=9
x=1
5)2х-19 = 7х+31
7x-2x=-19-31
5x=-50
x=-10
1) √₅+₁₁=√₁₆=₄
2)√₁₀₀-₉₁=√₉=₃
3)√₁,₂₉⁺₂,₇₁=√₄=₄
4)√₃₁,₁⁻₆,₁=√₃₇,₂