Y=(x+11)*e^(x-11)
y`=1*e^(x-11)+(x+11)*e^(x-11)=e^(x-11)(1+x+11)=e^(x-11)(x+12)=0
e^(x-11)>0 при любом х
х+12=0⇒х=-12
_ +
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-12
min
y(-2)=(-12+11)*e^(-12-11)=-e^-23=-1/e^23
(-12;-1/e^23)-точка минимума
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[16-4(4-a)]/[a(4-a)] = [16-16+4a]/[a(4-a)]=4/(4-a)
4/(4+12)= 4/16=1/4
Решение
y = (sin2x - 5)³
y` = 3(sin2x - 5)² * 2cos2x = 6 * (sin2x - 5)² * cos2x