Решение смотри на фотографии
8x³ - 1 = 23 + 8x³ - 12x
8x³ - 8x³ + 12x = 23 + 1
12x = 24
x = 24/12
x = 2
[tex]tg435+tg375=\frac[sin(435+375)]
{cos435
cos375}=\frac{sin810}{
cos435
cos375=\frac{90}{cos75
cos15}[\tex][tex]=\frac{1}{
cos75 cos15}=\frac{1}\frac{cos
(75-15)+cos(75+15)}{2}}=\frac{2}{cos60+cos90}=
\frac{2}{\frac{1}{2}+0}=4[\tex]
А)4:24=6
б) -
№5
√12+108=√120