- ( x² - 2x+ 1) + 4x - 4 + 5 = - x² + 2x - 1 + 4x + 1 = - x² + 6x
2)
![\frac{3x+1}{2} = \frac{2x-3}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B3x%2B1%7D%7B2%7D+%3D+%5Cfrac%7B2x-3%7D%7B5%7D+)
![\frac{3x+1}{2} - \frac{2x+3}{5} =0](https://tex.z-dn.net/?f=+%5Cfrac%7B3x%2B1%7D%7B2%7D+-+%5Cfrac%7B2x%2B3%7D%7B5%7D++%3D0)
первую дробь умножаем на 5. Вторую дробь на 2.
![\frac{15x+5}{10} - \frac{4x+6}{10}](https://tex.z-dn.net/?f=+%5Cfrac%7B15x%2B5%7D%7B10%7D+-+%5Cfrac%7B4x%2B6%7D%7B10%7D+)
![\frac{15x+5-4x+6}{10} =[tex] \frac{11x+11}{10}](https://tex.z-dn.net/?f=+%5Cfrac%7B15x%2B5-4x%2B6%7D%7B10%7D+%3D%5Btex%5D+%5Cfrac%7B11x%2B11%7D%7B10%7D+)
11x=1,1
x=0,1
3)
![\frac{x-3}{6} +x= \frac{2x-1}{3} - \frac{4-x}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx-3%7D%7B6%7D+%2Bx%3D+%5Cfrac%7B2x-1%7D%7B3%7D+-+%5Cfrac%7B4-x%7D%7B2%7D+)
![\frac{x-3}{6} +x- \frac{2x+1}{3} + \frac{4-x}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx-3%7D%7B6%7D+%2Bx-+%5Cfrac%7B2x%2B1%7D%7B3%7D+%2B+%5Cfrac%7B4-x%7D%7B2%7D+)
приводим к общему знаменателю
первую дробь не умножаем . х - умножаем на 6.вторую дробь умножаем на 2 . А третью дробь на 3 БУДЕТ :
![\frac{x-3}{6} - \frac{6x}{6} - \frac{4x-2}{6} + \frac{12-3x}{6}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx-3%7D%7B6%7D+-+%5Cfrac%7B6x%7D%7B6%7D+-+%5Cfrac%7B4x-2%7D%7B6%7D+%2B+%5Cfrac%7B12-3x%7D%7B6%7D+)
![\frac{x-3+6x-4x+2+12-3x}{6}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx-3%2B6x-4x%2B2%2B12-3x%7D%7B6%7D+)
=
![\frac{11}{6}](https://tex.z-dn.net/?f=+%5Cfrac%7B11%7D%7B6%7D+)
=
![1 \frac{5}{6}](https://tex.z-dn.net/?f=1+%5Cfrac%7B5%7D%7B6%7D+)
Ответ :
![1 \frac{5}{6}](https://tex.z-dn.net/?f=1+%5Cfrac%7B5%7D%7B6%7D+)
При a≥8; оригинале задаче пропущено.
![\sqrt{(\sqrt{a+4\sqrt{a-4}}-\sqrt{a-4\sqrt{a-4}})^2}=](https://tex.z-dn.net/?f=%5Csqrt%7B%28%5Csqrt%7Ba%2B4%5Csqrt%7Ba-4%7D%7D-%5Csqrt%7Ba-4%5Csqrt%7Ba-4%7D%7D%29%5E2%7D%3D)
![\sqrt{a+4\sqrt{a-4}-2\sqrt{a+4\sqrt{a-4}}\sqrt{a-4\sqrt{a-4}} +a-4\sqrt{a-4}}=](https://tex.z-dn.net/?f=%5Csqrt%7Ba%2B4%5Csqrt%7Ba-4%7D-2%5Csqrt%7Ba%2B4%5Csqrt%7Ba-4%7D%7D%5Csqrt%7Ba-4%5Csqrt%7Ba-4%7D%7D%20%2Ba-4%5Csqrt%7Ba-4%7D%7D%3D)
![\sqrt{2a-2\sqrt{a^2-16(a-4)}}=\sqrt{2a-2\sqrt{a^2-16a+64}}=\sqrt{2a-2\sqrt{(a-8)^2}}=\sqrt{2a-2(a-8)}}=\sqrt{2a-2a+16}}=\sqrt{16}=4](https://tex.z-dn.net/?f=%5Csqrt%7B2a-2%5Csqrt%7Ba%5E2-16%28a-4%29%7D%7D%3D%5Csqrt%7B2a-2%5Csqrt%7Ba%5E2-16a%2B64%7D%7D%3D%5Csqrt%7B2a-2%5Csqrt%7B%28a-8%29%5E2%7D%7D%3D%5Csqrt%7B2a-2%28a-8%29%7D%7D%3D%5Csqrt%7B2a-2a%2B16%7D%7D%3D%5Csqrt%7B16%7D%3D4)