<span>(sqrt(x^2+6x+9))-(sqrt(x^2-2x+1))=V(x+3)^2 -V(x-1)^2= I x+3 I - I x-1I</span>
F'(x)=4x^3+4x
f'(x)=0
4x^3+4x=0
4x(x^2+1)=0
Ответ: 0
<span>1)√7,5<√7,6
2)1/3=0,(3)⇒√1/3>√0,3
3)√0,1>√0,01
4)2,16<2,1(6)⇒√2,16<√(2 1/6)
5)2,6²=6,76⇒√7>2,6
6)5/6=55/66 U 6/11=36/66⇒√5/6>√6/11
7)3,2²=10,24⇒3,2>√9,8
8)1/3=0,(3)⇒√1/3=√0,(3)
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