Sin(3x+3)-sin(π/2-(x-1))=0
Применим формулу sina-sinb=2sin(a-b)/2*cos(a+b)2
[3x+3-(п/2-(х-1)]/2=(3х+3-п/2+х-1)/2=(4x+2-п/2)/2=2х+1-п/4
[3x+3+(п/2-(х-1)]/2=(3х+3+п/2-х+1)/2=(2x+4+п/2)/2=x+2+п/4
2sin(2x+1-π/4)cos(x+2+π/4)=0
sin(2x+1-π/4)=0
2x+1-π/4=πn
2x=π/4-1+πn
x=π/8-1/2+πn/2
cosx(x+2+π/4)=0
x+2+π/4=π/2+πn
x=π/4-2+πn
а)
х<span>²-4х<span>²+3=0</span></span>
<span><span>-3х<span>²+3=0</span></span></span>
<span><span><span>-3(х<span>²-1)=0</span></span></span></span>
<span><span><span><span><span>х²-1=0</span></span></span></span></span>
<span><span><span><span><span>(х-1)(х+)=0</span></span></span></span></span>
|х-1=0 = > х=1
|х+1=0 х=-1
Ответ:- 1;1
б)х<span>²+9х=0</span>
<span>х(х+9)=0</span>
<span>|х=0</span>
<span>|х=9</span>
<span>Ответ: 0;9</span>
в) <span>7х²-х-8=0</span>
D=1+224=225=15<span>²</span>
х=(15+1)/14=16/14=8/7
х=(-15+1)/14=-14/14=-1
Ответ:-1;8/7
г) 2х²-50=0
<span><span>х²-25=0</span></span>
(х-5)(х+5)=0
|х=5
|х=-5
Ответ:-5:5
1 (x-10)^3-x^3= (x-10-x)(x^2+10x+100)=-10(x^2+10x+100)
2.y^3+(7-y)^3=(y+7-y)(y^2-y(7-y)+(7-y)^2)=7(y^2-7y+y^2+49-7y-y^2)=7(-14y+y^2+49)