![\frac{3tg63-3tg18}{1+tg63tg18}=3( \frac{tg63-tg18}{1+tg63tg18})=3tg(63-18)=3tg45=3 \\ sin \frac{ \pi x}{6} - \sqrt{3} cos \frac{ \pi x}{6} =2 \\ \sqrt{1^2+ (\sqrt{3})^2 } *( \frac{1}{\sqrt{1^2+ (\sqrt{3})^2 }} *sin \frac{ \pi x}{6}- \frac{ \sqrt{3} }{\sqrt{1^2+ (\sqrt{3})^2 } } *cos \frac{ \pi x}{6}) =2 \\ 2*( \frac{1}{2} *sin \frac{ \pi x}{6} - \frac{ \sqrt{3} }{2} *cos \frac{ \pi x}{6} )=2 \\ \frac{1}{2} *sin \frac{ \pi x}{6} - \frac{ \sqrt{3} }{2} *cos \frac{ \pi x}{6} = 1 \\ ](https://tex.z-dn.net/?f=+%5Cfrac%7B3tg63-3tg18%7D%7B1%2Btg63tg18%7D%3D3%28+%5Cfrac%7Btg63-tg18%7D%7B1%2Btg63tg18%7D%29%3D3tg%2863-18%29%3D3tg45%3D3+%5C%5C+%0Asin+%5Cfrac%7B++%5Cpi+x%7D%7B6%7D+-+%5Csqrt%7B3%7D+cos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%3D2+%5C%5C+%0A+%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D+%2A%28+%5Cfrac%7B1%7D%7B%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D-++%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D+%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D%29+%3D2+%5C%5C+%0A2%2A%28+%5Cfrac%7B1%7D%7B2%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+-+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%29%3D2+%5C%5C+%0A+%5Cfrac%7B1%7D%7B2%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+-+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%3D+1+%5C%5C+%0A)
Продолжение прикреплено в виде картинки:
Пусть числа: (n-1), n, (n+1)
(n-1)n(n+1) = n(n² - 1) = 8(n-1 + n + n+1) = 24n
n² - 1 = 24
n² = 25
n = 5
Числа: 4; 5; 6
4² + 5² + 6² = 16 + 25 + 36 = 77
Ответ: 77
1) D=256=16 в квадрате
х1= 16:4=4
х2=-16:4=-4
Решение смотри на фотографии