Ответ:
1) -1+3·0= -1
2) 2-(-1)·(-3)= 2+1·(-3) = -1
3) (1+(-3))·2 = (1-3)·2 = -4
4)(3-1,2)·2= 3,6
5)(4-2)+(3-(-1)) = 2+(3+1) = 6
6) (0-(-4)) - (-2-3) = (0+4) -(-5) =4+5=9
7) 0,5-(1/2-(-1,2)) = 0,5 - (0,5+1,2) = -1,2
8) 5,2-(1,3-2,8)-2,8 = 3,9
Объяснение:
(1/2)√12+(1/3)√27+(1/4)√48=(1/2)√(4·3)+(1/3)√(9·3)+(1/4)√(16·3)=
=(1/2)·2√(3)+(1/3)·3√(3)+(1/4)·4√(3)=3√(<span>3)
</span>[(√64)·25]/<span>√25=8</span>·25/5=40
14¹⁰ + 14² + 196⁶ - 183² =
= 14¹⁰ + (14²)⁶ + (14² - 183²) =
= 14¹⁰ + 14¹² - (183² - 14² ) =
= 14¹⁰ * 1 + 14¹⁰ * 14² - (183 - 14)(183 + 14) =
= 14¹⁰ ( 1 + 14²) - 169 * 197 =
= 14¹⁰ * ( 1 + 196) - 169 * 197 =
= 14¹⁰ * 197 - 169 * 197 =
= 197 * ( 14¹⁰ - 169 ) =
= 197 * (14¹⁰ - 13² )
sin(a+pi)=-sina cos(pi/2+a)=-sina sin(a-2pi)=-sin(2pi-a)=-(-sina)=sina
-3sina-2(-sina)/sina=-3sina+2sina/sina=-1
B8) 5sin^2a+11cos^2a=9 5sin^2a+5cos^2a+6cos^2a=9 1+6cos^2a=9
6cos^2a=8 cos^2a=8/6
1+tg^2a=1/coa^2a =>tg^2a=6/8-1=-2/8=-1/4
B10) 4sin(a+pi)+7cos(pi/2+a)=-4sina-7sina=-11sina=-11*1/4=-11/4
sin(a+pi0=-sina cos(pi/2+a)=-sina
B9) 4sina+2cosa/(5sina-16cosa)=1 => 4sina+2cosa-5sina+16cosa=0
-sina+18cosa=0(/cosa) -tga+18=0 tga=-18
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