А(а^2-4) это очень легко)
16x^2-49=0;
(4x-7)(4x+7)=0;
4x-7=0 или 4x+7=0
4x=7
x=1.75.
4x=-7
x=-1.75.
Ответ: 1.75;-1.75.
1)= (ах-ау)+(zx-zy)=a(x-y)+z(x-y)=(a+z)(x-y)
$$$$$$$$
2) =(x^2-xy)-(6x-6y)=x(x-y)-6(x-y)=(x-6)(x-y)
$$$$$$$$$
(x+y)(y+p)=xy+xp+y^2+yp.
(2-y)(3y-8)(4a^2+b^2)=
=(6y-16-3y^2+8y)(4a^2+b^2)=
=(14y-16-3y^2)(4a^2+b^2)=
=56a^2y+14b^2y-64a^2-16b^2-12a^2y^2-3b^2y^2