Sin 5x = 1 - 2Cos² 3x
Sin 5x = - Cos 6x
Sin 5x + Cos 6x = 0
Sin 5x + Sin(π/2 - 6x) = 0
2Sin(π/4 - х/2)Сos( 11x/2 - π/4) = 0
а) Sin (π/4 - х/2) = 0 или б) Cos(11x/2 - π/4) = 0
π/4 - х/2 = πn, n∈Z 11x/2 - π/4 = π/2 + πк, к ∈Z
-x/2 = πn + π/4, n ∈Z 11x/2 = π/2 + π/4 + πк, к∈Z
x = -2πn - π/2, n ∈Z x = 3π/22 + 2πк/11, к ∈Z
Решение задания смотри на фотографии
1)a1=-16 a2=8⇒q-a2/a1=-1/2sn=-16*(1-(-1/2)^n)/(1+1/2)=2/3*(-16)*(1-(-1/2)^n)=
-32/3*(1-(-1/2)^n)=-32/3*(1-(-2)^-n)=-32/3+1/3*(-2)^5*(-2)^-n)=-32/3+1/3*(-2)^5-n
2)Sn=b1*(1-(1/4)^n)/(1-1/4)=84
b1*(1-(1/2)^n)*4/3=84
b1*(1-(1/2)^n=84*3/4=63
b1=63/(1-(1/4)^n)
5.52=69-27.6y
27.6y=69-5,52
y=69-5.52
_______ = 2.3
27.6