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Y`=2(x+2)*e^(3-x)-e^(3-x)*(x+2)²=(x+2)*e^(3-x)*(2-x-2)=-x(x+2)*e^(3-x)=0
e^(3-x)>0при любом х
x=0 x=-2
_ + _
-------------(-2)----------------(0)-------------------
min mfx
ymax=4e³
<span>М(11п/4)
cos(11п/4) =-</span><span><span>√2/2</span>
sin(11п/4) = </span><span>√2/2
М(-41п/6)
cos(-41п/6) = -1/2
sin(-41п/6) = -</span><span>√3/2
М(117п)</span>
cos(117п) = -1
sin(117п) = 0
2а в кубе=8а
12а в квадрате=144а
8а+144а+18а=170а
Вот фотография. Решение там