2a-ac-2c+c^2=a(2-c)-c(2-c)=(2-c)(a-c)
А³+2а+а²+2=(а³+а²)+(2а+2)=а²(а+1)+2(а+1)=(а+1)(а²+2)
(X-3y)(x+3y)-(x-3y)^2=(x^2-9y^2)-(x^2-6xy+9y^2)=x^2-9y^2-x^2+6xy-9y^2=6xy-18y^2=6y(x-3y)
![1) 9^x-4*3^x=-3\\ 3^{2x}-4*3x+3=0\\ 3^x=a\\ a^2-4a+3=0\\ D=16-12=4\\ a_1=\frac{4+2}{2}=3\\ a_2=1;\\ 3^x=3\\ x=1;\\ 3^x=1\\ x=0](https://tex.z-dn.net/?f=1%29+9%5Ex-4%2A3%5Ex%3D-3%5C%5C+3%5E%7B2x%7D-4%2A3x%2B3%3D0%5C%5C+3%5Ex%3Da%5C%5C+a%5E2-4a%2B3%3D0%5C%5C+D%3D16-12%3D4%5C%5C+a_1%3D%5Cfrac%7B4%2B2%7D%7B2%7D%3D3%5C%5C+a_2%3D1%3B%5C%5C+3%5Ex%3D3%5C%5C+x%3D1%3B%5C%5C+3%5Ex%3D1%5C%5C+x%3D0+)
Ответ: 1 и 0
![5) 5^{x-1} +0.2^(x-2) *5 =26\\ 5^{x-1}+5^{-x+2}*5=26\\ 5^{x-1}+5^{-x+2+1}=26\\ 5^{x-1}+5^{-x+3}=26\\ \frac{5^x}{5}+\frac{5^3}{5^x}=26 \ |*5^x*5\\ 5^{2x}+5^4-26*5*5^x=0\\ 5^{2x}+625-130*5^x=0\\ 5^x=t\\ t^2-130t+625=0\\ D=130^2-4*1*625=16900-2500=14400\\ \sqrt{14400}=120\\ t_1=\frac{130+120}{2}=125\\ t_2=\frac{130-120}{2}=5\\ 5^x=125\\ 5^x=5^3\\ x=3;\\ 5^x=5\\ x=1.](https://tex.z-dn.net/?f=5%29+5%5E%7Bx-1%7D+%2B0.2%5E%28x-2%29+%2A5+%3D26%5C%5C+5%5E%7Bx-1%7D%2B5%5E%7B-x%2B2%7D%2A5%3D26%5C%5C+5%5E%7Bx-1%7D%2B5%5E%7B-x%2B2%2B1%7D%3D26%5C%5C+5%5E%7Bx-1%7D%2B5%5E%7B-x%2B3%7D%3D26%5C%5C+%5Cfrac%7B5%5Ex%7D%7B5%7D%2B%5Cfrac%7B5%5E3%7D%7B5%5Ex%7D%3D26+%5C+%7C%2A5%5Ex%2A5%5C%5C+5%5E%7B2x%7D%2B5%5E4-26%2A5%2A5%5Ex%3D0%5C%5C+5%5E%7B2x%7D%2B625-130%2A5%5Ex%3D0%5C%5C+5%5Ex%3Dt%5C%5C+t%5E2-130t%2B625%3D0%5C%5C+D%3D130%5E2-4%2A1%2A625%3D16900-2500%3D14400%5C%5C+%5Csqrt%7B14400%7D%3D120%5C%5C+t_1%3D%5Cfrac%7B130%2B120%7D%7B2%7D%3D125%5C%5C+t_2%3D%5Cfrac%7B130-120%7D%7B2%7D%3D5%5C%5C+5%5Ex%3D125%5C%5C+5%5Ex%3D5%5E3%5C%5C+x%3D3%3B%5C%5C+5%5Ex%3D5%5C%5C+x%3D1.)
Ответ: 3 и 1
![6) 9^x+6^x=2^{2x}+1\ |:6^x\\ \frac{9^x}{6^x}+\frac{6^x}{6^x}-\frac{4^x}{6^x}-1=0\\ \frac{3^x}{2^x}+1-\frac{2^x}{3^x}-1=0\\ \frac{3^x}{2^x}-\frac{2^x}{3^x}=0\\ 3^{2x}-2^{2x}=0\\ (3-2)^{2x}=0\\ 1^{2x}=0\\ 1^x=0\\ 1^x=1^0\\ x=0\\](https://tex.z-dn.net/?f=6%29+9%5Ex%2B6%5Ex%3D2%5E%7B2x%7D%2B1%5C+%7C%3A6%5Ex%5C%5C+%5Cfrac%7B9%5Ex%7D%7B6%5Ex%7D%2B%5Cfrac%7B6%5Ex%7D%7B6%5Ex%7D-%5Cfrac%7B4%5Ex%7D%7B6%5Ex%7D-1%3D0%5C%5C+%5Cfrac%7B3%5Ex%7D%7B2%5Ex%7D%2B1-%5Cfrac%7B2%5Ex%7D%7B3%5Ex%7D-1%3D0%5C%5C+%5Cfrac%7B3%5Ex%7D%7B2%5Ex%7D-%5Cfrac%7B2%5Ex%7D%7B3%5Ex%7D%3D0%5C%5C+3%5E%7B2x%7D-2%5E%7B2x%7D%3D0%5C%5C+%283-2%29%5E%7B2x%7D%3D0%5C%5C+1%5E%7B2x%7D%3D0%5C%5C+1%5Ex%3D0%5C%5C+1%5Ex%3D1%5E0%5C%5C+x%3D0%5C%5C+)
Непонятно в пимерах где заканчивается степень......
Привет.Я желаю тебе счасть,хороших оценок.А вот я тебе что скажу если хочешь ты можешь через Photomath сделать а если нет то тогда я тебе сейчас помогу