графиком данной функции является парабола ветви вниз, значит нужно найти вершину
1)
![6* \frac{2}{11} *5* \frac{1}{8} +1* \frac{9}{11} * 5* \frac{1}{8} = \frac{12}{11} * \frac{5}{8} + \frac{9}{11} * \frac{5}{8} = \frac{5}{8} ( \frac{12}{11} + \frac{9}{11} )= \frac{5}{8} *\frac{21}{11}=](https://tex.z-dn.net/?f=6%2A++%5Cfrac%7B2%7D%7B11%7D+%2A5%2A+%5Cfrac%7B1%7D%7B8%7D+%2B1%2A+%5Cfrac%7B9%7D%7B11%7D+%2A+5%2A+%5Cfrac%7B1%7D%7B8%7D+%3D++%5Cfrac%7B12%7D%7B11%7D+%2A+%5Cfrac%7B5%7D%7B8%7D+%2B+%5Cfrac%7B9%7D%7B11%7D+%2A++%5Cfrac%7B5%7D%7B8%7D+%3D+%5Cfrac%7B5%7D%7B8%7D+%28+%5Cfrac%7B12%7D%7B11%7D+%2B+%5Cfrac%7B9%7D%7B11%7D+%29%3D+%5Cfrac%7B5%7D%7B8%7D+%2A%5Cfrac%7B21%7D%7B11%7D%3D+)
![= \frac{105}{88} =1 \frac{17}{88}](https://tex.z-dn.net/?f=%3D+%5Cfrac%7B105%7D%7B88%7D+%3D1+%5Cfrac%7B17%7D%7B88%7D+)
или условие должно было быть таким:
![6 \frac{2}{11} *5 \frac{1}{8} +1 \frac{9}{11} *5 \frac{1}{8}= 5 \frac{1}{8}(6 \frac{2}{11} +1 \frac{9}{11})=5 \frac{1}{8} *8= \frac{41}{8} *8=41](https://tex.z-dn.net/?f=6+%5Cfrac%7B2%7D%7B11%7D+%2A5+%5Cfrac%7B1%7D%7B8%7D+%2B1+%5Cfrac%7B9%7D%7B11%7D+%2A5+%5Cfrac%7B1%7D%7B8%7D%3D+5+%5Cfrac%7B1%7D%7B8%7D%286+%5Cfrac%7B2%7D%7B11%7D+%2B1+%5Cfrac%7B9%7D%7B11%7D%29%3D5+%5Cfrac%7B1%7D%7B8%7D+%2A8%3D+%5Cfrac%7B41%7D%7B8%7D+%2A8%3D41)
2)
![6,71*2,8-4,71*2,8=2,8(6,71-4,71)=2,8*2=5,6](https://tex.z-dn.net/?f=6%2C71%2A2%2C8-4%2C71%2A2%2C8%3D2%2C8%286%2C71-4%2C71%29%3D2%2C8%2A2%3D5%2C6)
1) x+10=5^3 x=125-10=115
2) 3x-2=x+6 2x=8 x=4
3) <span>log2(4-x)*5=log2(x-1) 20-5x=x-1 6x=21 x= 3.5
ОДЗ: (1;4)</span>
Составим пропорцию
20-100%
19-х
Х=95%
Если х=0
3х+2у-6=0⇒ 2у= 6-3х⇒ у= (6-3х)/2 подставим у= (6-3*0)/2 = 3
5х-7у-14=0⇒ 5х+14=7у⇒ (5х+14)/7= у подставим (5*0+14)/7= 2