4(sinα+cosα)^2-4sin2α=4(sin^2α+2sinαcosα+cos^2α)-8sinαcosα=4(2sinαcosα+1)-8sinαcosα=8sinαcosα+1-8sinαcos<span>α</span>=1
А.xz+xy+2z+2y = ...x(z+y)+2(z+g)<span>
Б.2ab-2ac+3b-3c = ...2</span>a(b-c)+3(b-c)<span>
В.5ax+10ay+bx+2by = ...5</span>a(x+2y)+b(x+2y)<span>
Г.3ac+6bc+7ax+14 bx = ...3</span>c(a+2b)+7x(a+2b)<span>
Д.2ax+2xy-an-yn = ...2</span>x(a+y)-n(a+y<span>)</span>
Решение смотрите в вложении
А) =(10х+3)²
Ответ: 1)
б) =(¹/₃ у-3х)²=(¹/₃* (-27)-3*11)²=(-9-33)²=(-42)²=1764