Question

4 cos a-6 sin a/3sina-cosa Если tg = 3

Answer 1

$\dfrac{4cosa-6sina}{3sina-cosa} = \\ \\ = \dfrac{ \frac{4cosa-6sina}{cosa} }{ \frac{3sina-cosa}{cosa} }= \\ \\ = \dfrac{4-6tga}{3tga-1}= \\ \\ = \dfrac{4-6*3}{3*3-1} = \\ \\ = \dfrac{-14}{8}= \\ \\ = -\dfrac{7}{4}$