log(a) b + log(a) c = log(a) bc
a^n*a^m = a^(n+m)
ОДЗ y>0 x>0
log(2) y + log(2) 3 = log(2) x
log(2) 3y = log(2) x
x= 3y
3^x*3^y^2 = 3^4
x+y^2 = 4 подставляем из первого
y^2 + 3y - 4 = 0
D=9+16=25 y12=(-3+-5)/2 = -4 1
y1=-4 Нет по ОДЗ
y2=1
x=3y=3
ответ (3 1)
2-6х-15=3х-15-6
2-15+15+6=3х+6х
8=9х
х=8/9
=((64/5)(15/4)-(48/11)*(33/8))/((16/7)/(4/35))=
=(48-18)/20=30/20=1,5.
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