<span>(x^2+2x)^2-(x+1)^2-55=0
(x</span>²+2x)²-(x²+2x+1)²-55=0
x²+2x=t
t²-(t+1)²-55=0
t²-t²-2t-1-55=0
2t=-56
t=-28
x²+2x=28
x²+2x-28=0
D=4+112=116
x1=(-2-2√29)/2=-1-√29 U x2=-1+√29
<span>1) a(x-y)+4(x-y) = </span><span>(x-y)(а+4)
2) 3x-3y+ax-ay</span> = <span>3(x-y) + a(x-y</span>) = (x-y)(<span>3+a</span>)
Решение смотри на фотографии