Question

Вычислить: arcsin 0 - arccos √2/2 - (arctg√3/3) / (arcctg√3)

Answer 1

$arcsin 0 - arccos \dfrac{\sqrt{2}}{2} - (arctg\dfrac{\sqrt3}{3} ) / (arcctg\sqrt3)= \\\\ 0-\dfrac{\pi }{4} - \dfrac{\pi}{6} /\dfrac{\pi }{6} =\\ \\ -\dfrac{\pi}{4} -1$