Question

9x^2 - 6x - 1 = 0 через дискриминант решите

Answer 1

Решение:
$9 {x}^{2} - 6x - 1 = 0 \\ d1 = 9 + 9 = 18 \\ x = \frac{3 + \sqrt{18} }{9} = \frac{1 + \sqrt{2} }{3} \\ x = \frac{3 + \sqrt{18} }{9} = \frac{1 - \sqrt{2} }{3}$

Answer 2

D=36-4*9*(-1)=72
x1=(6-√72)/18. x2=(6+√72)/18