HgO -> Hg
----------------
ΔHh= m/M = 7/201 = 0.034
ΔHgO = 0.034
m(HgO) = 0.034* (201+16) = 7.4 г масса оксида ртути
4.6 X
2Na+2H2O=2NaOH+H2
46 22.4
X=22.4*4.6/46=2.24 л сутек
1) 2Na + 2H2O = 2NaOH + H2
2) Na2O + H2O = 2NaOH
3) Ba(OH)2 + K2SO4 = 2KOH + BaSO4
4) KOH + Na = NaOH + K