Lim┬(x→0)〖(1+x-x^2)/(〖2x〗^2+5x+4)〗 =
=lim┬(x→0)〖(1+x-x^2):x^2/(〖2x〗^2+5x+4):x^2〗=
=lim┬(x→0)〖(1/x^2+x/x^2-x^2/x^2)/(4x^2/x^2+5x/x^2+4/x^2)〗=
= lim┬(x→0))〖(1/x^2+1/x-1)/(4+5/x+4/x^2)〗=-1/4
x² + y²<span>=9 и прямой 2x - 4y = 6
2x=6+4y
x=3+2y
9+12y+4y^2+y^2=9
5y^2+12y=0
y(5y+12)=0
y=0
x=3
y=-12/5
x=-9/5
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Ответ:
-16
Объяснение:
(-1)¹⁷- 100÷10 - 25÷5 = -1 - 10 -5
sin(- 47п/6) cos 32п/3=sinpi\6*cos2pi\3=1\2*-1\2=-1\4