........................................
1)(sinx-3cosx)`=sin`x-(3cosx)`=cosx+3sinx
2)(cos(4x-п/3))`=-sin(4x-п/3)*(4x-п/3)`=-4sin(4x-п/3)
(x²-1)²+(x²-6x-7)²=0
[(x+1)(x-1)]²+[(x+1)(x-7)]²=0
(x+1)²[(x-1)²+(x-7)²]=0
(x+1)²(2x²-16x+50)=0
2(x+1)²(x²-8x+25)=0 D во второй скобке <0
x+1=0
х=-1
(ctg²a -cos²a)*tg²a=(cos²a/sin²a-cos²a)sin²a/cos²a=cos²a(1/sin²a-1)sin²a/cos²a= (1/sin²a-1)sin²a=(1-sin²a) sin²a/sin²a=cos²a