Question

Реши уравнение

Answer 1

$\sqrt[3]{x} - 2\sqrt[6]{x} = 0$

$\sqrt[3]{x}=2\sqrt[6]{x}$

$x^{2} =64x$

$x^{2}-64x=0$

$x*(x-64)=0$

$x = 0$

$x - 64 = 0$

$x=0$

$x=64$

$\sqrt[3]{0} - 2\sqrt[6]{0} = 0$

$\sqrt[3]{64} - 2\sqrt[6]{64} = 0$

$0=0$

$0=0$

$x=0$

$x = 64$

$x_{1} = 0$

$x_{2} = 64$

Answer 2

$\sqrt[6]{x}$=у

у²-2у=0

у=0       у-2=0  у=2

$\sqrt[6]{x}$ =0            $\sqrt[6]{x}$ =2

х=0      х=2^6=64