1) |x| + 6 = 13;2) 1x1 - 7 = -12;3) 7|x) - 3 = 0;4) [x - 51 = 4;5) 19 + x1 = 0;6) lx - 41 = -2;7) 13x +41 = 28) |2x + 11 + 13 =

Question

4 года назад

15

1) |x| + 6 = 13;2) 1x1 - 7 = -12;3) 7|x) - 3 = 0;4) [x - 51 = 4;5) 19 + x1 = 0;6) lx - 41 = -2;7) 13x +41 = 28) |2x + 11 + 13 =

1) |x| + 6 = 13;
2) 1x1 - 7 = -12;
3) 7|x) - 3 = 0;
4) [x - 51 = 4;
5) 19 + x1 = 0;
6) lx - 41 = -2;
7) 13x +41 = 2
8) |2x + 11 + 13 = 14;
9) ||x1 - 31 = 5.

Знания

Алгебра

2 ответа:

kseniya83 [31] · Answer 1 · 2020-03-25T19:16:52+03:00

kseniya83 [31]4 года назад

0 0

Ответ:

1) (x)+6=13

x+6=13

x=13-6

x = 7

x = - 7

advokatOR [21] · Answer 2 · 2020-03-25T19:33:06+03:00

advokatOR [21]4 года назад

0 0

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