(2х+ху)+(х-3ху)
3ху+х-3ху
4ху-3ху=1ху
(/ дробь)
2) а)√5-√3/3√5-3√3=√5-√3/3(√5-√3)=1/3
б)16(4-∛3)/61 +∛3=64-16∛3/61 +∛3=64-16∛3+61∛3/61=64+45∛3/61
3) а)∛32=∛2³×4=∛2³∛4=2∛4
Решение задания приложено
X2+3x-10=0
D=3^2-4×1×(-10)=9+40=49
x1=-3+7/2×1=4/2=2
x2=-3-7/2×1=-10/2=-5
1/4-1/2*log9 4 1/4 log9 2 2log9 2 log9 4
81 =81 / 81 = 3 / 9 = 3 / 9 = 3/4
log125 8 2log 5^3 8 log5 8^(2/3)
25 = 5 =5 = 8^(2/3)=4
log7 2 2log7 2 log7 4
49 = 7 = 7 =4
(3/4+4)*4=3+16=19