Question

Приведите многочлен к стандартному виду: 1) 4х^2*1/2y-1/3ab9a+4y*4/5x^2+aba; 2) 5a1/2b+2/3a(1/4b^2)-5b(0.5a)-1/3a^2(1/15ab)

Answer 1

$1) 4x^2* \frac{1}{2}y- \frac{1}{3}ab9a+4y* \frac{4}{5} x^{2} +aba= \\ =2 x^{2} y-3a^2b+3.2x^{2} y+a^2b=5.2 x^{2} y-2a^2b \\ \\ 2)5a \frac{1}{2}b+ \frac{2}{3}a( \frac{1}{4}b^2 ) -5b(0.5a)- \frac{1}{3}a^2( \frac{1}{15}ab ) = \\ =2.5ab+ \frac{1}{6}ab^2-2.5ab- \frac{1}{45}a^3b= \frac{1}{6}ab^2- \frac{1}{45}a^3b$