(5+25)*(5^0+5^2+5^4<span>...5^(1005*2) </span>)
(1 2) (0+2+4+6)
<span>(1+3<span>x)+(x^2-2x)-(2x^2-x)=</span> 1+3<span>x+x^2-2x-2x^2</span>+x=- <span>x^2</span>+2<span>x+1</span></span>
ΔABC,<C=90,CH_|_AB,CD-биссектриса,<HCD=30
<HCD=30⇒<CDH=90-30=60
<DCB=45
<CDB=180-60=120 смежный <<CDH
<B=180-(<DCB+<CDB)=180-(120+45)=15
<A=90-<B=90-15=75
(х²+14ху+49у²)/(х² - 49у²) * (21у-3х)/(7х²+49ху) =(х+7у)²/((х-7у)(х+7у)) * (3(7у-х))/(7х(х+7у)) =(3(7у-х))/(7х(х-7у)))=( -3(х-7у))/(7х(х-7у))= - 3/7х
при х=9, у=49
- 3/(7*9)= - 1/21