Question

Найдите корни 10x^2-13-3

Answer 1

$10x {}^{2} - 13 - 3 = 10x {}^{2} - 16 = 2(5x {}^{2} - 8)$

Answer 2

$10 {x}^{2} - 13x - 3 = 0 \\ d = {b}^{2} - 4ac = 169 - 120 = 49 \\ x = \frac{b + - \sqrt{d} }{2a} = \frac{13 + - 7}{20} = 0.3 \: and \: 1$