240/x-240/(x-5)+4=0
x(x-5)≠0⇒x≠0,x≠5
240(x-5)-240*x+4x(x-5)
240x-1200-240x+4x²-20x=0
4x²-20x-1200=0
x²-5x-300=0
x1+x2=5 U x1*x2=-300
x1=-15 U x2=20
Для этого нужно взять производную от функции и приравнять ее нулю. У'=2х-2=0. Х=1. Умин=у(1)=1-2+3=2
sin3π = 0
cos3π = -1
tg3π = 0
ctg3π не существует
<span>sin(-4π) = 0</span>
<span>cos(<span>-4π) = 1</span></span>
<span><span>tg(<span>-4π) = 0</span></span></span>
<span><span><span>ctg(<span>-4π) не существует</span></span></span></span>
<span><span><span><span>sin(-π/2) = -1</span></span></span></span>
<span><span><span><span>cos(-π/2) = 0</span></span></span></span>
<span><span><span><span>tg(-π/2) не существyет</span></span></span></span>
ctg(-π/2) = 0
sin(5π/2) = 1
cos(5π/2) = 0
tg(5π/2) не существует
cos(5π/2) = 0
sin(-5π/6) = -1/2
cos(-5π/6) = -√3/2
tg(-5π/6) = 1/√3
ctg(-5π/6) = √3
sin(3π/4) = √2/2
cos(3π/4) = - √2/2
tg(3π/4) = -1
ctg(3π/4) = -1