А) <span>(х+4)^6=x^6+4^6=x^6+4096
б) </span>(3z – 2y^3)^7=3z^7-128*y^21
A⁷+a⁵+2a²+2=(a⁷+a⁵)+(2a²+2)=a⁵·(a²+1)+2·(a+1)=(a²+1)·(a⁵+2);
8xy-4y+2x²-x=4y·(2x-1)+x·(2x-1)=(2x-1)·(4y+x);
Если правильно понял 5/12 *36/15=(5*36)/(12*15)=1
B1 = 49
b2 = 7
q = b2/b1 = 7/49 = 1/7
S = b1/(1 - q) = 49/(1 - 1/7) = 49/6/7 = 343/6