ОДЗ: x>0
a²+a-2≤0
(a+2)(a-1)≤0
+ - +
________[-2]_____________[1]_________
a∈[-2;1]
<span>\left \{ {log_{0,5}x \geq -2} \atop {log_{0,5}x \leq 1}} \right. =\ \textgreater \ \left \{ {{log_{0,5}x \geq log_{0,5}4} \atop {log_{0,5}x \leq log_{0,5}0,5}} \right.\; \; \; \; \; \; 0\ \textless \ 0,5\ \textless \ 1\\\\ \left \{ {{x \leq 4} \atop {x \geq 0,5}} \right. [/tex]
</span>
Ответ: [0,5;4]
................................,........
{х+2у+2у=11
{<span>5х-3у=3
</span><span>{х+4у=11 /х3
</span><span>{5х-3у=3 /х4
</span><span>{3х+12у=33
</span>20х-12у=12
23х=45
х=45/23
5(45/23)-3у=3
225/23-3у=3
-3у=3-225/23
-3у=-156/23
3у=156/23
у=52/23
Смотри решение в приложении