2'=0.
х'=1.
(3х)'=3.
(Х^3)= 3х^2.
(4х^4+4)'=16х^3.
(1/2•х^4+2/3•х^3+2х^2+2)'=2х^3+2х^2+4х.
((3х^3-2)(2х^2-3))'=9х^2•(2х^2-3)+4 х •(3х^3-2).
((3х^2)/(х+2))'=(6х•(х+2)-3х^2)/(х+2)^2=3х/(х+2).
5ˣ⁺¹ = 25
<span>5ˣ⁺¹ = 5</span>²
х + 1 = 2
х = 2 - 1
х = 1
= х^(5+6+b) - x^(16-7-8)=x^(11+b) - x^(1)=x * (x^(10+b) - 1 )