Решение задания смотри на фотографии
(6x+1) - (3-2x) = 14
(6x+2x) - (3-1) = 14
8x - 2 = 14
8x = 14+2
8x = 16
x = 16 ÷ 8
x = 2
3х²=18х
3х²-18х=0
3х(х-6)=0
х=0 или х=6
:)
M³+27=(m+3)(m²-3m+9)
y³+1/8=(y+1/2)(y²-1/2y+1/4)
8+c³=(2+c)(4-2c+c²)
8/27+z³=(2/3+z)(4/9-2/3z+z²)
1-x³=(1-x)(1+x+x²)
b³-1/125=(b-1/5)(b²+1/5+1/25)
y³-x³=(y-x)(y²+xy+x²)
1/27-t³=(1/3-t)(1/9+1/3t+t²)
6)
(9х+6)/12 - (6х-18)/12<3
(9х+6-6х+18)/12<3
(3х+24)/12<3
3х+24<36
3х<12
х<4