Ответ:
2,4<6‾√<2,5;
9−6‾√.
Cначала неравенство умножим на −1 и поменяем знаки, затем прибавим 9:
2,4<6‾√<2,5∣∣⋅(−1)−2,4>−6‾√>−2,5;−2,5<−6‾√<−2,4;−2,5+9<−6‾√+9<−2,4+9;
6,5<9−6‾√<6,6.
Объяснение:
Графическое подтверждение на изображении
1) 1 - ( - 4) = 1 + 4 = 5;
2) 0 - ( - 7) = 0 + 7 = 7;
3) - 2.5 - 3.5 = - 6.
<span>1)(a x^2+b x^2)x^3 = a x^5 + b x^5</span>
<span><span>2)(x x^2-y x^2)x^3 = x^6 - y x^5</span></span>
<span><span><span>3)(2m x^2-3n x^2)x^3 = 2m x^5 - 3n x^5</span></span></span>
<span><span><span><span>5)(4m x^3+n x^2)x^3 = 4m x^6 + n x^5</span></span></span></span>
<span><span><span><span><span>6)(10p x^4-6q x^2)x^3 = 10p x^7 - 6q x^5</span></span></span></span></span>
<span><span><span><span><span><span>7)(7u x^3-9v x^4)x^3 = 7u x^6 - 9vx^7</span></span></span></span></span></span>
<span><span><span><span><span><span><span>8)(10x x^3+3y x^2)x^3 = 10x^7 + 3y x^5</span></span></span></span></span></span></span>
1)49-d²=(7-d)(7+d)
2)m²-10m+25=(m-5)²
3)3x-9xy²=3x(1-3y²)
4)(c-4d)(c+4d)=c²-16d²
5)x²+16x+64=(x+8)² 6)y²+6y+9=(y+3)²