2 4у^2 2у
( ------- – ------------):(------------------ –
2у+х (2у+х)^2 (2у–х)(2у+х)
1 2(2у+х)–4у^2 2у–(2у+х)
– --------) = ------------------- : ----------------
2у–х (2у+х)^2 (2у–х)(2у+х)
4у^2+2х–4у^2 2у–2у–х
= --------------------- : ------------------ =
(2у+х)^2 (2у–х)(2у+х)
2х(2у–х)(2у+х) 2(2у–х)
= --------------------- = – ------------
–х(2у+х)^2 (2у+х)
X+y=5
x-y=15
y=5-x
x-y=15
x-(5-x)=15
x-5+x=15
2x=20
x=10
y=5-10
y=-5
<span>Ответ:(10;-5)</span>