sin*cos = 1 => 3sin*cos = 3
2-2i / -2+3i = (2-2i) (-2-3i) / (-2+3i)(-2-3i)= -4-6i+4i+6i² / 4-9i² = -4-2i-6 / 4+9 =
= -10-i/13
Решение
tg (arcsin1/3) = sin(arcsin1/3) / cos(arcsin1/3)
1) sin(arcsin1/3) =1/3
2) cos²(arcsin1/3) = 1-sin²(arcsin1/3) = 1 - (1/3)² =1-1|9 =8/9, тогда cos(arcsin1/3) = √8/3
3) tg (arcsin1/3)= (1/3) : (√8/3) = 1/√8 = 1/2√2=√2/4