Question

Помогитеее даю 30баллов

Answer 1

$\sqrt{ \frac{x-4}{2-3x} } =1$
$( \sqrt{ \frac{x-4}{2-3x} } ) ^{2}=1 ^{2}$     $\frac{x-4}{2-3x} \geq 0$
$\frac{x-4}{2-3x} =1$
$\frac{x-4-2+3x}{2-3x}=0$
$\frac{4x-6}{2-3x} =0$
$\frac{2(2x-3)}{2-3x} =0$
$2x-3=0$                  $2-3x \neq 0$
$2x=3$                        $3x \neq 2$
$x=1,5$                       $x \neq \frac{2}{3}$
Ответ: 1,5