дано
m(CaCO3) = 40 g
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V(CO2)-?
2HCL+CaCO3-->CaCL2+H2O+CO2
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 40 / 100 = 0.4 mol
n(CaCO3) = n(CO2) = 0.4 mol
V(CO2) = n*Vm = 0.4 * 22.4 = 8.96 L
ответ 8.96 л
Cu(NO₃)₂ + 2NaOH = Cu(OH)₂ + 2NaNO₃
Cu²⁺+2NO₃⁻+2Na⁺+2OH⁻ = Cu(OH)₂ + 2Na⁺+2NO₃⁻
Cu²⁺+2OH⁻ = Cu(OH)₂
Cu(NO₃)₂ + Fe = Cu + Fe(NO₃)₂
Cu²⁺+2NO₃⁻ + Fe = Cu + Fe²⁺+2NO₃⁻
Cu²⁺+ Fe = Fe²⁺ + Cu
NaOH + HCl = NaCl + H₂O
Na⁺+OH⁻+H⁺+Cl⁻ = Na⁺+Cl⁻ + H₂O
H⁺+OH⁻ = H₂O
2NaOH + SO₃ = Na₂SO₄ + H₂O
2Na⁺+ 2OH⁻ + SO₃ = 2Na⁺+SO₄²⁻+H₂O
2OH⁻+SO₃ = SO₄²⁻ + H₂O
CaCO₃ + 2HCl = CaCl₂ + H₂O + CO₂
CaCO₃ + 2H⁺+2Cl⁻ = Ca²⁺ + 2Cl⁻ + H₂O + CO₂
CaCO₃ + 2H⁺ = Ca²⁺ + H₂O + CO₂
CaO + 2HCl = CaCl₂ + H₂O
CaO + 2H⁺+2Cl⁻ = Ca²⁺+2Cl⁻+H₂O
CaO + 2H⁺ = Ca²⁺+H₂O
1.5mol x L
2CH3OH+2Na=2CH3CONa+H2
2mol 22.4 L
x=1.5*22.4/2=16.8 L
4Al (порошок) + 3O2 = 2Al2O3
Al2O3 + 6HCl (к/t) = 2AlCl3 + 3H2O
AlCl3 + 3NaOH (р) = Al(OH)3 + 3NaCl
<span>Al(OH)3 + 3HNO3 = Al(NO3)3 + 3H2O
</span>4Al(NO3)3<span> (t) = 2Al2O3 + 12NO2 + 3O2
</span><span>Al2O3 + Na2O (t) = 2NaAlO2 (сплавление)</span>
Массовая доля элемента вычисляется по формуле w = Ar (C) * n / Mr (MgCO3) * 100%Mr (MgCO3) = 24 + 12 + 16*3 = 84Ar (C) = 12n - количество атомов углерода в формуле (в данном случае 1)w (C) = (12 * 1 / 84) * 100% = 14,285%